1. Prove by (weak) mathematical induction that (+i | 1≤i≤n : 2i + 4) = n2 + 5n for all n ≥ 0.
2. Prove by (weak) mathematical induction that (+i | 0≤i≤n : bi) = (bn+1 - 1) / (b-1) for all n ≥ 0.
3. Define f : ℕ → ℕ as follows:
f.0 | = | 1 |
f.1 | = | 3 |
f.n | = | 2·f(n−1) − f(n−2) (for n≥2) |
Prove by (strong) mathematical induction that f.n = 2n+1 for all n ≥ 0.
4. Define g : ℕ → ℕ as follows:
g.0 | = | 1 |
g.1 | = | 5 |
g.n | = | 7·g(n−1) − 10·g(n−2) (for n≥2) |
Prove by (strong) mathematical induction that g.n = 5n for all n ≥ 0.
5.
* / \ / \ / \ * * / \ | / \ | * * * / \ / \ * * | / \ | / \ * * * | | | | * * |
Root is a leaf T0 |
Root has one child T1 |
Root has two children T2 |
---|---|---|
* |
* | | | | * / \ / \ / TC \ +-------+ |
* / \ / \ / \ / \ * * / \ / \ / \ / \ / TL \ / TR \ +-------+ +-------+ |
The height of a rooted tree is equal to the length of a longest path among all paths from the root to the leaves. Recursively, the height of a rooted tree is zero if the root is its only node and, otherwise, the height is one plus the height of its "tallest" proper subtree (which would be a subtree rooted at one of the children of the root).
Referring to the diagram above, we have
Prove by (weak) mathematical induction that, for all n≥0, every rooted binary tree having at least 2n nodes has height at least n.
To clarify, what is to be proved is that, for all n≥0 and all rooted binary trees T,
where v(T) is the number of nodes/vertices in T and h(T) is the height of T.
Hint: Regarding the induction step, suppose that T is a rooted binary tree having at least 2n+1 nodes. If T is of the form of T1, how many nodes must be in TC? If T is of the form of T2, how many nodes must be in larger among TL and TR?